Answer Key to Grade 11 Review Problems

Note: answers that are "definition type" questions or can be simply verified by text book reference are not included.

Unit 1: Matter and Chemical Bonding

Q.3a) 15.0g oxygen 3b) Sample i) 70%Fe Sample ii) 77.9% Fe

Law of Constant Composition concludes they are not the same.

Q5) Ag-109: 47 protons/47 electrons/62 neutrons

Cl-35: 17 protons/17electrons/18 neutrons

Mg-25: 12 protons/12electrons/13 neutrons

Q6) S: 2/8/6 Ca: 2/8/8/2 Ne: 2/8 Li: 2/1

Q7) (2n2 rule where "n"= energy level) n=1 = 2e n=2 = 8e n=3= 18e n=4=32

Q16)

Q17)a) lead (IV) sulphide b) silicon dioxide c) dinitrogen tetroxide

d) copper (II) nitrate e) carbon tetrachloride f) aluminum phosphate

g) zinc chloride h) iron (III) sulphate i) carbonic acid

j) hydrosulphuric acid k) potassium iodide l) calcium sulphide

m) potassium perchlorate n) acetic acid o) nitrogen dioxide

p) carbon monoxide q) magnesium carbonate r) cobalt (II) nitrite

s) phosphoric acid t) nitric acid u) hydrochloric acid

v) phosphorus pentabromide w) sulphuric acid x) chloric acid

y) sulphur hexafluoride z) magnesium sulphate heptahydrate

Q18)a) ZnO b) Hg₃N c) Ca(NO₃)₂ d) PbCO₃ e) LiI

f) Sn(CH₃COO)₂ g) AgCl h) Ni₂S₃ i) CO₂ j) P₂O₃

k) CuSO₄ l) Al(NO₃)₃ m) HNO₂(aq) n) NH₃ o) (NH₄)₃PO₄

p) Be(ClO₃)₂ q) HBrO₃(aq) r) H₂O s) HF(aq) t) N₂O

u) Rb₂S v) CoP w) BCl₃ x) Fe₂(SO₃)₃

y) AuClO z) Ba(OH)₂ 8H₂O

Q19) NH³ trigonal pyramidal and polar, CCl₄ tetrahedral and non-polar,

PF₃ trigonal pyramidal and polar, CO₂ linear and non-polar,

HCN linear and polar, HCF₃ tetrahedral and polar,

BH₃ planar triangular and non-polar, HI liniear and polar,

O₂ linear and non-polar, H₂O bent and polar

Q20)a) product: P₂O₃ or P₂O₅ (balance accordingly)

b) products: ZnCl₂ and Fe (balance accordingly)

c) products: H₂O and AlCl₃ (balance accordingly)

d) no reaction

e) products: CaO and CO₂

f) product: AgCl (balance)

g) no reaction

h) products: NaCl(aq) and CaCO₃(s) (balance)

Q21)a) exothermic neutralization reaction b) exothermic synthesis

c) exothermic synthesis d) exothermic single displacement

e) endothermic decomposition f) exothermic double displacement

g) endothermic decomposition

Unit 2: Quantities in Chemical Reactions

Q2) 120g/mol Q3) 194g Q4) 0.390mol

Q6) a) 1.39x10²³ nitrogen molecules b) 2(1.39x10²³) atoms

Q7) a) C₂H₃ClO b) C₄H₆Cl₂O₂

Q8) a) Mg is limiting b) 150g c) 99%

Q9) a) 340g b) 0.91g c) 0.258mol Q10) 2.03g

Unit 3: Solutions and Solubility

Q1) MgCl₂ ---> Mg²⁺(aq) + 2Cl^1-(aq)

Q2) a) 3Pb(NO₃)₂(aq) + 2Al(s) ---> 3Pb(s) + 2Al(NO₃)₃(aq)

c) 3Pb²⁺(aq) + 2Al(s) ---> 3Pb(s) + 2Al³⁺(aq)

Q3) net ionic: H⁺ + OH^- ---> H₂O

Q5) 0.0214M Q6) 52.9g Q7) 15.6mL of stock

Q8) 0.101M Q9) a) 286mL b) 1.9g

Q10) 0.75M

Unit 4: Gases

Q1) volume decreases by a factor of 3. Boyles law

Q2) volume increase by factor of 4. Charles law

Q3) 3.5 L Q4) 298 kPa Q5) -48^oC Q6) 32.1 kPa

Q7) a) 1.96 g/mL b) sink c) 0.171 mol d) 43.6 g/mol e) CO₂

Q8) a) CH₃O b) mm = 62 g/mol so C₂H₆O₂ Q9) 5.08 L

Q10) a) 1.08 L I₂ b) 0.360 L N₂

Unit 5: Hydrocarbons

Q1) a) 4-ethyl-3-methyl-3-heptene b) 1,3-diethyl-2,4-dimethylcyclopentane

c) 4-methyl-2-pentyne d) 3,6-diethyl-4,5-dimethyldecane

e) 3-methyl-1-cyclobutene f) 5-ethyl-6-methyl-2-octyne

Q2)

Q3) a) 2C₃H₆ + 9O₂ --> 6CO₂ + 6H₂O

Q5) C₁₇H₃₆ + H₂ --> C₈H₁₈ + C₉H₂₀

Q6) Top (lowest boiling point)-- Propane--Butane--Octane--Decane--Kerosene--Paraffin wax --Bottom (highest B.P)

As length of carbon chaing increases, strength of London forces increases, resulting in higher boiling points.